Subsections

# 6.4 Tensile fractures and wellbore breakdown

Wellbore tensile (or open mode) fractures occur when the minimum principal stress on the wellbore wall goes below the limit for tensile stress: the tensile strength . Unconsolidated sands have no tensile strength. Hence, an open-mode fracture occurs early after effective stress goes to zero. The minimum hoop stress is located on the wall of the wellbore and at and (Fig. 6.14): (6.16)

Notice that we have added a temperature term that takes into account wellbore cooling, an important phenomenon that contributes to tensile fractures in wellbores. Matching the lowest value of hoop stress with tensile strength permits finding the mud pressure that would produce a tensile (or open mode) fracture: (6.17)

and therefore (6.18)

The subscript of corresponds to “breakdown” pressure because in some cases when , a mud pressure can create a hydraulic fracture that propagates far from the wellbore and causes lost circulation during drilling. When and , the mud pressure will produce short tensile fractures around the wellbore that do not propagate far from the wellbore.

In the equations above we have added the contribution of thermal stresses where is the linear thermal expansion coefficient and is the change in temperature ( for ). Wellbores are usually drilled and logged with drilling mud cooler than the formation . Cooling leads to solid shrinkage and stress relaxation (a reduction of compression stresses). Hence, ignoring thermal stresses is conservative for preventing breakouts but it is not for tensile fractures and should be taken into account when calculating .

Fig. 6.15 shows an example of calculation of the local minimum principal stress around a wellbore. The locations with the lowest stress align with the direction of the far-field maximum stress in the plane perpendicular to wellbore axis. PROBLEM 6.3: Calculate the maximum mud weight (ppg) in a vertical wellbore for avoiding drilling-induced tensile fractures in a site onshore at 7,000 ft of depth where 4,300 psi and 6,300 psi and with hydrostatic pore pressure. The rock mechanical properties are 3,500 psi, 0.6, and = 800 psi.

SOLUTION
The problem variables are the same of problem 6.1. The breakdown pressure in the absence of thermal effects is psi psi psi psi psi

This pressure can be achieved with an equivalent circulation density of ## 6.4.1 Identification of tensile fractures in wellbores

Similarly to breakouts, drilling-induced tensile fractures can be identified and measured with borehole imaging tools (Fig. 6.16). The azimuth of tensile fractures coincides with the direction of in vertical wells. 