Applications of stresses result in solid deformation and displacements. Figure 3.7 shows an example of a solid body and the corresponding displacement vector field (traces the displacements from the original to the deformed state). In this particular case, the solid is anchored at the bottom and deforms due to the application of a force (from left to right) on the top. Hence, displacements at the bottom are zero and displacements on the top are the maximum.
Yet, absolute displacements are not enough to determine stresses. A solid may translate or rotate in space without development of any internal stresses required to equilibrate external actions (imagine a cookie “floating” in zero gravity within the International Space Station https://www.youtube.com/watch?v=q5uV4fTV0Zo).
Let's look at Figure 3.8 in order to relate displacements to strains:
Strains do not quantify the absolute value of displacements, but its variation in space (derivative with respect to ). All other strains are found with similar equations in the 3D case. Similarly to the stress tensor, strains can be organized in a tensor where elements in the diagonal contribute to volumetric strain, and off-diagonal elements are shear strains.
The summation of all diagonal terms yields the volumetric strain
EXAMPLE 3.2: Demonstrate the equality in Eq. 3.8 from simple geometrical concepts. Hint: the initial volume of the solid is .
The definition of volumetric strain is the ratio between the change of volume and the initial volume :
For an elementary cubic volume with initial volume and volume after deformation , the equation above results
Let us discard all the products containing and also because they are much smaller than the other terms including just one ( ), then